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If [tex]f(5) = 288.9[/tex] when [tex]r = 0.05[/tex] for the function [tex]f(t) = Pe^{rt}[/tex], then what is the approximate value of [tex]P[/tex]?

A. 24
B. 371
C. 225
D. 3520

Answer :

To solve this problem, we need to find the value of [tex]\( P \)[/tex] in the function [tex]\( f(t) = P \cdot e^{rt} \)[/tex], given that [tex]\( f(5) = 288.9 \)[/tex] and [tex]\( r = 0.05 \)[/tex].

Let's break this down step-by-step:

1. Identify the equation: The function is given as [tex]\( f(t) = P \cdot e^{rt} \)[/tex].

2. Substitute the known values: We know [tex]\( f(5) = 288.9 \)[/tex], [tex]\( r = 0.05 \)[/tex], and [tex]\( t = 5 \)[/tex]. So, we substitute these into the equation:

[tex]\[
288.9 = P \cdot e^{0.05 \times 5}
\][/tex]

3. Simplify the exponent: Calculate the expression within the exponent:

[tex]\[
0.05 \times 5 = 0.25
\][/tex]

Thus, the equation becomes:

[tex]\[
288.9 = P \cdot e^{0.25}
\][/tex]

4. Calculate [tex]\( e^{0.25} \)[/tex]: The value of [tex]\( e^{0.25} \)[/tex] is approximately 1.284.

5. Solve for [tex]\( P \)[/tex]: Rearrange the equation to solve for [tex]\( P \)[/tex]:

[tex]\[
P = \frac{288.9}{e^{0.25}}
\][/tex]

[tex]\[
P = \frac{288.9}{1.284}
\][/tex]

6. Calculate [tex]\( P \)[/tex]: Dividing gives us an approximate value of:

[tex]\[
P \approx 225
\][/tex]

From the options given, the closest approximate value is [tex]\( \boxed{225} \)[/tex].

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