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How many times does 15 go into 31?
- 2 times, with a remainder of 1

How many times does 15 go into 13?
- 0 times, with a remainder of 13

How many times does 15 go into 135?
- 9 times, with a remainder of 0

Calculate the quotient:

[tex]\[ 3,135 \div 15 = \square \][/tex]

[tex]\[
\begin{array}{r}
-30 \\
\hline
13 \\
\end{array}
\][/tex]

[tex]\[
\begin{array}{r}
0 \\
\hline
135 \\
-135 \\
\hline
0 \\
\end{array}
\][/tex]

Answer :

Sure, let's break down the solution step-by-step:

1. How many times does 15 go into 31?

You start by dividing 31 by 15. Fifteen goes into 31 exactly 2 times (15 * 2 = 30). Subtract 30 from 31 to find the remainder:

[tex]\[
31 - 30 = 1
\][/tex]

So, 15 goes into 31 a total of 2 times, with a remainder of 1.

2. How many times does 15 go into 13?

Fifteen cannot fully go into 13 because 13 is less than 15. Therefore, it goes 0 times with a remainder of 13.

3. How many times does 15 go into 135?

Divide 135 by 15. Fifteen goes into 135 exactly 9 times (15 * 9 = 135). Since there is no leftover, the remainder is 0.

4. What is the quotient of 3,135 divided by 15?

Now, divide 3,135 by 15. When you do this calculation, the result is precisely 209 with no remainder because:

[tex]\[
3135 \div 15 = 209 \quad \text{(since 15 * 209 = 3135)}
\][/tex]

So, the quotient of 3,135 divided by 15 is 209.

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