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Solve the triangle: [tex]\alpha = 65^\circ[/tex], [tex]\beta = 45^\circ[/tex], and [tex]a = 30[/tex].

A. [tex]b = 23.4[/tex], [tex]\gamma = 70^\circ[/tex], [tex]c = 28.9[/tex]
B. [tex]b = 38.5[/tex], [tex]\gamma = 70^\circ[/tex], [tex]c = 28.9[/tex]
C. [tex]b = 38.5[/tex], [tex]\gamma = 70^\circ[/tex], [tex]c = 31.1[/tex]
D. [tex]b = 23.4[/tex], [tex]\gamma = 70^\circ[/tex], [tex]c = 31.1[/tex]

Answer :

Answer:

b= 23.4,. γ = 70°, c= 28.9

Step-by-step explanation:

To solve the triangle with given α = 65°, β = 45°, and a = 30, we can use the law of sines:

b/sin(β) = a/sin(α)

b/sin(45°) = 30/sin(65°)

b ≈ 23.4

Then, to find angle γ, we can use the fact that the sum of angles in a triangle is 180°:

γ = 180° - α - β

γ ≈ 70°

To find side c, we can again use the law of sines:

c/sin(γ) = a/sin(α)

c/sin(70°) = 30/sin(65°)

c ≈ 28.9

Therefore, the solution is b = 23.4, γ = 70°, and c = 28.9.

Note that there is no other possible solution, as the given angles and side lengths do not allow for multiple triangles to be formed.

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