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Answer :
To find out how much more Toby's chemistry textbook weighs than his geometry textbook, we need to subtract the weight of the geometry textbook from the weight of the chemistry textbook.
1. Weights of the Textbooks:
- Chemistry textbook: [tex]\(\frac{8}{10}\)[/tex] of a pound.
- Geometry textbook: [tex]\(\frac{4}{10}\)[/tex] of a pound.
2. Subtract the Weight of the Geometry Textbook from the Chemistry Textbook:
[tex]\[
\frac{8}{10} - \frac{4}{10} = \frac{4}{10}
\][/tex]
3. Simplify the Fraction if Possible:
- The fraction [tex]\(\frac{4}{10}\)[/tex] can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 2.
[tex]\[
\frac{4}{10} = \frac{4 \div 2}{10 \div 2} = \frac{2}{5}
\][/tex]
So, the chemistry textbook weighs [tex]\(\frac{2}{5}\)[/tex] pounds more than the geometry textbook.
1. Weights of the Textbooks:
- Chemistry textbook: [tex]\(\frac{8}{10}\)[/tex] of a pound.
- Geometry textbook: [tex]\(\frac{4}{10}\)[/tex] of a pound.
2. Subtract the Weight of the Geometry Textbook from the Chemistry Textbook:
[tex]\[
\frac{8}{10} - \frac{4}{10} = \frac{4}{10}
\][/tex]
3. Simplify the Fraction if Possible:
- The fraction [tex]\(\frac{4}{10}\)[/tex] can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 2.
[tex]\[
\frac{4}{10} = \frac{4 \div 2}{10 \div 2} = \frac{2}{5}
\][/tex]
So, the chemistry textbook weighs [tex]\(\frac{2}{5}\)[/tex] pounds more than the geometry textbook.
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