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Answer :
The velocity of the canoe and the other camper after the camper leaves the boat is approximately 1.641 m/s.
How to solve for velocity
Given:
Mass of camper 1 (leaving the boat), = 80.0 kg
Velocity of camper 1 (leaving the boat), = 4.0 m/s
Combined mass of the canoe and the other camper = 115 kg
Velocity of the canoe and the other camper after the camper leaves, vf
To find the velocity and direction of the canoe and the other camper after the camper leaves the boat, we can use the conservation of momentum:
Total momentum before = Total momentum after
Since the other camper stays in the boat, their velocity is considered zero. Solving for vf:
(80.0 kg * 4.0 m/s) + (115 kg * 0) = (80.0 kg + 115 kg) * vf
320 kg·m/s + 0 = 195 kg * vf
320 kg·m/s = 195 kg * vf
vf = 320 kg·m/s / 195 kg
vf ≈ 1.641 m/s
The velocity of the canoe and the other camper after the camper leaves the boat is approximately 1.641 m/s.
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