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Which line is perpendicular to a line that has a slope of [tex]-\frac{5}{6}[/tex]?

A. line JK
B. line LM
C. line NO
D. line PQ

Answer :

To determine which line is perpendicular to a line with a slope of [tex]\(-\frac{5}{6}\)[/tex], we need to find the slope of the perpendicular line.

The slope of a line that is perpendicular to another line is the negative reciprocal of the original slope. The negative reciprocal is found by flipping the fraction and changing the sign.

1. The original slope given is [tex]\(-\frac{5}{6}\)[/tex].

2. To find the negative reciprocal, first take the reciprocal of [tex]\(-\frac{5}{6}\)[/tex], which is [tex]\(-\frac{6}{5}\)[/tex].

3. Then change the sign to get the negative reciprocal. If the reciprocal is [tex]\(-\frac{6}{5}\)[/tex], changing the sign gives us [tex]\(\frac{6}{5}\)[/tex].

To convert the fraction [tex]\(\frac{6}{5}\)[/tex] into a decimal, divide 6 by 5:

[tex]\[
\frac{6}{5} = 1.2
\][/tex]

So, the slope of the line that is perpendicular to a line with a slope of [tex]\(-\frac{5}{6}\)[/tex] is 1.2. The next step would be to identify which line among JK, LM, NO, or PQ has a slope of 1.2.

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