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If [tex]f(x)[/tex] is an exponential function of the form [tex]y = ab^x[/tex] where [tex]f(-3.5) = 6[/tex] and [tex]f(0) = 82[/tex], find the value of [tex]f(-0.5)[/tex] to the nearest hundredth.

Answer :

To solve the problem, we're given that [tex]\( f(x) = a \cdot b^x \)[/tex] is an exponential function, and we're asked to find the value of [tex]\( f(-0.5) \)[/tex]. Let's use the information provided about the values at certain points to determine the parameters [tex]\( a \)[/tex] and [tex]\( b \)[/tex], and then find [tex]\( f(-0.5) \)[/tex].

### Step 1: Determine the value of [tex]\( a \)[/tex]

The function [tex]\( f(x) = a \cdot b^x \)[/tex] evaluates to 82 when [tex]\( x = 0 \)[/tex].

[tex]\[ f(0) = a \cdot b^0 = a \][/tex]

Since [tex]\( f(0) = 82 \)[/tex], we find that:

[tex]\[ a = 82 \][/tex]

### Step 2: Use another point to find [tex]\( b \)[/tex]

We are given another point where [tex]\( f(-3.5) = 6 \)[/tex].

[tex]\[ f(-3.5) = a \cdot b^{-3.5} = 6 \][/tex]

Substituting [tex]\( a = 82 \)[/tex] into this equation, we have:

[tex]\[ 82 \cdot b^{-3.5} = 6 \][/tex]

To solve for [tex]\( b \)[/tex], divide both sides by 82:

[tex]\[ b^{-3.5} = \frac{6}{82} \][/tex]

Now, take both sides to the power of [tex]\( -\frac{1}{3.5} \)[/tex] to solve for [tex]\( b \)[/tex]:

[tex]\[ b = \left(\frac{6}{82}\right)^{-\frac{1}{3.5}} \][/tex]

### Step 3: Calculate [tex]\( f(-0.5) \)[/tex]

Now that we have [tex]\( a = 82 \)[/tex] and we've calculated [tex]\( b \)[/tex], we need to determine [tex]\( f(-0.5) \)[/tex].

[tex]\[ f(-0.5) = 82 \cdot b^{-0.5} \][/tex]

Substitute [tex]\( b \)[/tex] into this equation to find [tex]\( f(-0.5) \)[/tex]. Using the calculated [tex]\( b \)[/tex]:

[tex]\[ f(-0.5) \approx 56.44 \][/tex]

Thus, the value of [tex]\( f(-0.5) \)[/tex], rounded to the nearest hundredth, is approximately 56.44.

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