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Answer :
Sure! Let's go through each part of the question step-by-step:
a) Lab Report Percent Average:
- We need to calculate the average of the lab report grades.
- The grades are: 75, 90, 85, 69, 70, 75, 80, 75.
- To find the average, sum all the grades and then divide by the number of grades.
[tex]\[
\text{Average} = \frac{75 + 90 + 85 + 69 + 70 + 75 + 80 + 75}{8}
\][/tex]
[tex]\[
\text{Average} = \frac{619}{8} = 77.375
\][/tex]
So, the lab report percent average is 77.375.
b) Quiz Percent Average:
- We calculate the average of the quiz grades.
- The quiz grades are: 85, 80, 0, 60, 70, 80, 80, 75.
- Again, sum all the grades and divide by the total number of quizzes.
[tex]\[
\text{Average} = \frac{85 + 80 + 0 + 60 + 70 + 80 + 80 + 75}{8}
\][/tex]
[tex]\[
\text{Average} = \frac{530}{8} = 66.25
\][/tex]
Thus, the quiz percent average is 66.25.
c) Course Grade Before the Final:
- We use the weighted averages to find the overall course grade before the final exam.
- The weights are given for each component of the course.
[tex]\[
\text{Course Grade} = (66.25 \times 0.05) + (80 \times 0.20) + (70 \times 0.20) + (77.375 \times 0.15) + (85 \times 0.15)
\][/tex]
[tex]\[
\text{Course Grade} = 3.3125 + 16 + 14 + 11.60625 + 12.75
\][/tex]
[tex]\[
\text{Course Grade} = 57.66875
\][/tex]
Therefore, the course grade before the final is 57.66875.
d) Lowest Grade on the Final for a 'B' Average:
- To achieve at least a B (82%), we calculate the minimum score needed on the final exam.
- Let [tex]\( x \)[/tex] be the final exam grade needed:
[tex]\[
57.66875 + (x \times 0.25) \geq 82
\][/tex]
Solve for [tex]\( x \)[/tex]:
[tex]\[
x \times 0.25 \geq 82 - 57.66875
\][/tex]
[tex]\[
x \times 0.25 \geq 24.33125
\][/tex]
[tex]\[
x \geq \frac{24.33125}{0.25}
\][/tex]
[tex]\[
x \geq 97.325
\][/tex]
So, the lowest grade she can get on the final to achieve a B average is approximately 97.33.
a) Lab Report Percent Average:
- We need to calculate the average of the lab report grades.
- The grades are: 75, 90, 85, 69, 70, 75, 80, 75.
- To find the average, sum all the grades and then divide by the number of grades.
[tex]\[
\text{Average} = \frac{75 + 90 + 85 + 69 + 70 + 75 + 80 + 75}{8}
\][/tex]
[tex]\[
\text{Average} = \frac{619}{8} = 77.375
\][/tex]
So, the lab report percent average is 77.375.
b) Quiz Percent Average:
- We calculate the average of the quiz grades.
- The quiz grades are: 85, 80, 0, 60, 70, 80, 80, 75.
- Again, sum all the grades and divide by the total number of quizzes.
[tex]\[
\text{Average} = \frac{85 + 80 + 0 + 60 + 70 + 80 + 80 + 75}{8}
\][/tex]
[tex]\[
\text{Average} = \frac{530}{8} = 66.25
\][/tex]
Thus, the quiz percent average is 66.25.
c) Course Grade Before the Final:
- We use the weighted averages to find the overall course grade before the final exam.
- The weights are given for each component of the course.
[tex]\[
\text{Course Grade} = (66.25 \times 0.05) + (80 \times 0.20) + (70 \times 0.20) + (77.375 \times 0.15) + (85 \times 0.15)
\][/tex]
[tex]\[
\text{Course Grade} = 3.3125 + 16 + 14 + 11.60625 + 12.75
\][/tex]
[tex]\[
\text{Course Grade} = 57.66875
\][/tex]
Therefore, the course grade before the final is 57.66875.
d) Lowest Grade on the Final for a 'B' Average:
- To achieve at least a B (82%), we calculate the minimum score needed on the final exam.
- Let [tex]\( x \)[/tex] be the final exam grade needed:
[tex]\[
57.66875 + (x \times 0.25) \geq 82
\][/tex]
Solve for [tex]\( x \)[/tex]:
[tex]\[
x \times 0.25 \geq 82 - 57.66875
\][/tex]
[tex]\[
x \times 0.25 \geq 24.33125
\][/tex]
[tex]\[
x \geq \frac{24.33125}{0.25}
\][/tex]
[tex]\[
x \geq 97.325
\][/tex]
So, the lowest grade she can get on the final to achieve a B average is approximately 97.33.
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