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In the titration, 15.0 mL of CsOH solution is neutralized by 38.2 mL of 0.250 M HBr solution. What is the molarity of the CsOH solution?

A. 0.250 M
B. 0.375 M
C. 0.500 M
D. 0.750 M

Answer :

Final answer:

The molarity of the CsOH solution in the given titration problem can be calculated using the formula M1V1 = M2V2. After rearranging the formula to solve for the unknown and inserting the provided values, the result is 0.638 M.

Explanation:

In this chemistry problem, you are asked to find the molarity of the CsOH solution. This can be found by using the titration formula, where M1V1 = M2V2 (meaning molarity of solution 1 times volume of solution 1 equals molarity of solution 2 times volume of solution 2).

In our case, M2 is what we're trying to find (M2 being the molarity of the CsOH solution). If we rearrange the formula to solve for M2, we get M2 = (M1V1) / V2.

Insert the values: M2 = (0.250M * 38.2mL) / 15.0mL. When you calculate this, you get M2 = 0.638 M.

None of the options given in the question match this result, suggesting there might have been a mistake in the problem or in the provided options.

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