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Answer :
To determine the daughter nuclide resulting from the decay of [tex]\({ }_{83}^{210} \text{Bi}\)[/tex], we need to understand the type of decay involved.
1. Identify the type of decay: Bismuth-210 ([tex]\({ }_{83}^{210} \text{Bi}\)[/tex]) commonly undergoes beta minus (β⁻) decay. In beta minus decay, a neutron is converted into a proton within the nucleus.
2. Changes in the nucleus during beta minus decay:
- The atomic number increases by 1 because a neutron becomes a proton.
- The mass number (total protons and neutrons) remains unchanged because one neutron is simply converted into a proton.
3. Calculate the new atomic number and mass number:
- Start with [tex]\({ }_{83}^{210} \text{Bi}\)[/tex].
- Atomic number before decay: 83 (Bismuth).
- Atomic number after decay: 83 + 1 = 84.
- Mass number remains: 210.
4. Identify the element with the new atomic number:
- The element with atomic number 84 is Polonium (Po).
Therefore, the daughter nuclide after the beta minus decay of [tex]\({ }_{83}^{210} \text{Bi}\)[/tex] is [tex]\({ }_{84}^{210} \text{Po}\)[/tex] or Po-210.
1. Identify the type of decay: Bismuth-210 ([tex]\({ }_{83}^{210} \text{Bi}\)[/tex]) commonly undergoes beta minus (β⁻) decay. In beta minus decay, a neutron is converted into a proton within the nucleus.
2. Changes in the nucleus during beta minus decay:
- The atomic number increases by 1 because a neutron becomes a proton.
- The mass number (total protons and neutrons) remains unchanged because one neutron is simply converted into a proton.
3. Calculate the new atomic number and mass number:
- Start with [tex]\({ }_{83}^{210} \text{Bi}\)[/tex].
- Atomic number before decay: 83 (Bismuth).
- Atomic number after decay: 83 + 1 = 84.
- Mass number remains: 210.
4. Identify the element with the new atomic number:
- The element with atomic number 84 is Polonium (Po).
Therefore, the daughter nuclide after the beta minus decay of [tex]\({ }_{83}^{210} \text{Bi}\)[/tex] is [tex]\({ }_{84}^{210} \text{Po}\)[/tex] or Po-210.
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