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Answer :
Let's break down the problem and find the solutions step-by-step.
First Scenario: Heterozygous Male (Ww) and Homozygous Recessive Female (ww)
1. Parental Genotypes:
- Male: Ww
- Female: ww
2. Determine Possible Offspring Genotypes:
- We need to determine what genotypes are possible when these two are mated. Using a Punnett square, you place the alleles of one parent across the top and the other parent down the side.
```
| W | w |
--------------
w | Ww | ww |
w | Ww | ww |
```
3. Analyze the Offspring:
- Possible genotypes: Ww, ww, Ww, ww
- Offspring genotypes are 2 Ww and 2 ww, making a total of 4.
4. Calculate Probability of Heterozygous Offspring (Ww):
- There are 2 Ww (heterozygous) out of 4 total offspring.
- Probability = Number of Ww offspring / Total number of offspring = 2/4 = 0.5
So, 0.5 (or 50%) of the offspring will be heterozygous.
Second Scenario: Heterozygous (Ww) crossed with Homozygous Dominant (WW)
1. Parental Genotypes:
- One parent is Ww.
- The other parent is WW.
2. Determine Possible Offspring Genotypes:
- Similar to above, use a Punnett square:
```
| W | w |
--------------
W | WW | Ww |
W | WW | Ww |
```
3. Analyze the Offspring:
- Possible genotypes: WW, Ww, WW, Ww
- Offspring genotypes are 2 WW and 2 Ww, making a total of 4.
4. Calculate Probability of Homozygous Recessive Offspring (ww):
- There are 0 ww (homozygous recessive) out of 4 total offspring since all offspring have at least one W.
- Probability = Number of ww offspring / Total number of offspring = 0/4 = 0.0
Therefore, the probability of having a homozygous recessive offspring is 0.0 (or 0%).
These are the probabilities for each scenario based on the Punnett square analysis.
First Scenario: Heterozygous Male (Ww) and Homozygous Recessive Female (ww)
1. Parental Genotypes:
- Male: Ww
- Female: ww
2. Determine Possible Offspring Genotypes:
- We need to determine what genotypes are possible when these two are mated. Using a Punnett square, you place the alleles of one parent across the top and the other parent down the side.
```
| W | w |
--------------
w | Ww | ww |
w | Ww | ww |
```
3. Analyze the Offspring:
- Possible genotypes: Ww, ww, Ww, ww
- Offspring genotypes are 2 Ww and 2 ww, making a total of 4.
4. Calculate Probability of Heterozygous Offspring (Ww):
- There are 2 Ww (heterozygous) out of 4 total offspring.
- Probability = Number of Ww offspring / Total number of offspring = 2/4 = 0.5
So, 0.5 (or 50%) of the offspring will be heterozygous.
Second Scenario: Heterozygous (Ww) crossed with Homozygous Dominant (WW)
1. Parental Genotypes:
- One parent is Ww.
- The other parent is WW.
2. Determine Possible Offspring Genotypes:
- Similar to above, use a Punnett square:
```
| W | w |
--------------
W | WW | Ww |
W | WW | Ww |
```
3. Analyze the Offspring:
- Possible genotypes: WW, Ww, WW, Ww
- Offspring genotypes are 2 WW and 2 Ww, making a total of 4.
4. Calculate Probability of Homozygous Recessive Offspring (ww):
- There are 0 ww (homozygous recessive) out of 4 total offspring since all offspring have at least one W.
- Probability = Number of ww offspring / Total number of offspring = 0/4 = 0.0
Therefore, the probability of having a homozygous recessive offspring is 0.0 (or 0%).
These are the probabilities for each scenario based on the Punnett square analysis.
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