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If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, the offspring's genotype possibilities are:

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous Ww is crossed with a homozygous dominant WW, the probability of having a homozygous recessive offspring is:

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline W & WW & WW \\
\hline w & Ww & Ww \\
\hline
\end{array}
\]
[/tex]

Answer :

Sure, let's go through the solutions step by step:

### First Scenario:

We have a heterozygous male with genotype Ww mating with a homozygous recessive female with genotype ww. We need to find the probability of the offspring having each genotype.

1. Identify Parent Genotypes:
- Male: Ww
- Female: ww

2. Set Up a Punnett Square:

```
W w
----------
w | Ww ww
w | Ww ww
```

3. Determine the Offspring Genotypes:
- Ww (Heterozygous): From the Punnett Square, there are two possibilities (top left and bottom left squares).
- ww (Homozygous recessive): From the Punnett Square, there are two possibilities (top right and bottom right squares).

4. Calculate the Probabilities:
- Probability of Ww: 2 out of 4 squares = 1/2 or 50%
- Probability of ww: 2 out of 4 squares = 1/2 or 50%

### Second Scenario:

Now, we consider a cross between a heterozygous Ww and a homozygous dominant WW, and find out the probability of having a homozygous recessive (ww) offspring.

1. Identify Parent Genotypes:
- One parent is Ww (heterozygous)
- The other parent is WW (homozygous dominant)

2. Set Up a Punnett Square:

```
W W
----------
W | WW WW
w | Ww Ww
```

3. Determine the Offspring Genotypes:
- WW: From the Punnett Square, there are two possibilities (top row).
- Ww: From the Punnett Square, there are two possibilities (bottom row).

4. Analyze for Homozygous Recessive (ww):
- There is 0 chance for an offspring to be ww because there are no squares for ww in the Punnett Square.

5. Calculate the Probability of Homozygous Recessive (ww):
- Probability of ww: 0 out of 4 squares = 0%

These steps show how we can determine the probabilities of different genotypes based on the genetic crosses provided.

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