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An electric bulb in your house is rated at 100 W, and a refrigerator is rated at 400 W. If these appliances are operated for 10 hours per day, what is the cost of the energy required to run them for 10 days at the rate of Rs. 8 per kWh?

Answer :

Final answer:

The cost of running a 100 W electric bulb and a 400 W refrigerator for 10 hours per day over 10 days at a rate of Rs. 8 per kWh is Rs. 400.

Explanation:

To calculate the cost of the energy required to run a 100 W electric bulb and a 400 W refrigerator for 10 hours per day over 10 days at the rate of Rs. 8 per kWh, we need to follow these steps:

  1. Calculate the total power consumption of both appliances in kilowatts (kW) by dividing the wattage by 1,000. This gives 0.1 kW for the bulb and 0.4 kW for the refrigerator.
  2. Multiply the power consumption by the number of hours per day and then by the number of days to find the total energy usage in kilowatt-hours (kWh).
  3. Finally, multiply the total energy usage by the cost per kWh to find the total cost.

We can see that:

  • The bulb uses 0.1 kW × 10 hours/day × 10 days = 10 kWh.
  • The refrigerator uses 0.4 kW × 10 hours/day × 10 days = 40 kWh.
  • Adding both, we get a total of 10 kWh + 40 kWh = 50 kWh.
  • Multiplying the total kWh by the cost rate gives 50 kWh × Rs. 8/kWh = Rs. 400.

Therefore, the total cost for operating both the electric bulb and refrigerator for 10 hours a day over 10 days is Rs. 400.

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