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What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high?

(Formula: [tex]PE = mgh[/tex])

A. 75 J
B. 735 J
C. 245 J
D. 37.8 J

Answer :

To find the potential energy, we use the formula

[tex]$$
PE = mgh,
$$[/tex]

where:
- [tex]$m$[/tex] is the mass,
- [tex]$g$[/tex] is the gravitational acceleration,
- [tex]$h$[/tex] is the height.

We are given:
- [tex]$m = 25\, \text{kg}$[/tex],
- [tex]$g = 9.8\, \text{m/s}^2$[/tex],
- [tex]$h = 3\, \text{m}$[/tex].

Now, substitute these values into the formula:

[tex]$$
PE = 25 \times 9.8 \times 3.
$$[/tex]

First, calculate the product of [tex]$25 \times 9.8$[/tex]:

[tex]$$
25 \times 9.8 = 245.
$$[/tex]

Then, multiply by [tex]$3$[/tex]:

[tex]$$
245 \times 3 = 735.
$$[/tex]

Thus, the potential energy of the bicycle at the top of the hill is

[tex]$$
\boxed{735\, \text{J}}.
$$[/tex]

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Rewritten by : Barada