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Jerald jumped from a bungee tower. If the equation that models his height, in feet, is [tex]h = -16t^2 + 729[/tex], where [tex]t[/tex] is the time in seconds, for which interval of time is he less than 104 feet above the ground?

A. [tex]t \ \textgreater \ 6.25[/tex]
B. [tex]-6.25 \ \textless \ t \ \textless \ 6.25[/tex]
C. [tex]t \ \textless \ 6.25[/tex]
D. [tex]0 \leq t \leq 6.25[/tex]

Answer :

To determine the interval of time where Jerald is less than 104 feet above the ground, we start with the equation that models his height:

[tex]\[ h = -16t^2 + 729 \][/tex]

We want to find when his height [tex]\( h \)[/tex] is less than 104 feet:

[tex]\[ -16t^2 + 729 < 104 \][/tex]

First, let's rearrange the inequality:

[tex]\[ -16t^2 < 104 - 729 \][/tex]

[tex]\[ -16t^2 < -625 \][/tex]

Next, divide both sides by -16, remembering to reverse the inequality sign because we're dividing by a negative number:

[tex]\[ t^2 > \frac{625}{16} \][/tex]

Now, solve for [tex]\( t \)[/tex] by taking the square root of both sides:

[tex]\[ t > \sqrt{\frac{625}{16}} \quad \text{or} \quad t < -\sqrt{\frac{625}{16}} \][/tex]

Calculating that gives:

[tex]\[ t > \frac{25}{4} \quad \text{or} \quad t < -\frac{25}{4} \][/tex]

Simplifying the values:

[tex]\[ t > 6.25 \quad \text{or} \quad t < -6.25 \][/tex]

Since time [tex]\( t \)[/tex] cannot be negative in this context, we only consider positive values of [tex]\( t \)[/tex]. Therefore, the interval where Jerald is less than 104 feet above the ground is:

[tex]\[ t > 6.25 \][/tex]

So, the correct choice is [tex]\( t > 6.25 \)[/tex].

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