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Answer :
To find the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, we need to understand what this number represents. This number, [tex]\(6.02 \times 10^{23}\)[/tex], is known as Avogadro's number, which is the number of atoms in one mole of a substance.
1. Atomic Mass Understanding:
- The atomic mass of potassium is given as 39.1. This value indicates the mass of one mole of potassium atoms, expressed in grams.
2. Mass of One Mole:
- Since one mole of potassium atoms is defined by Avogadro's number, which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms, the mass of these atoms is equivalent to the atomic mass, which is 39.1 grams.
3. Conclusion:
- Therefore, for [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, which is one mole, the mass will be 39.1 grams.
Thus, the correct answer is:
[tex]\[ \text{B. } 39.1 \, \text{g} \][/tex]
1. Atomic Mass Understanding:
- The atomic mass of potassium is given as 39.1. This value indicates the mass of one mole of potassium atoms, expressed in grams.
2. Mass of One Mole:
- Since one mole of potassium atoms is defined by Avogadro's number, which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms, the mass of these atoms is equivalent to the atomic mass, which is 39.1 grams.
3. Conclusion:
- Therefore, for [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, which is one mole, the mass will be 39.1 grams.
Thus, the correct answer is:
[tex]\[ \text{B. } 39.1 \, \text{g} \][/tex]
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