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Answer :
To solve the problem of identifying the expression equivalent to [tex]\(\frac{\log _2 128}{\log _2 16}\)[/tex], we can use a fundamental property of logarithms.
One useful property is:
[tex]\[
\frac{\log_a b}{\log_a c} = \log_c b
\][/tex]
This tells us that when you divide two logarithms with the same base, you can rewrite it as a single logarithm with the denominator’s value as the new base and the numerator's value as the argument (or power that the base must be raised to).
Applying this property to our expression:
[tex]\[
\frac{\log_2 128}{\log_2 16} = \log_{16} 128
\][/tex]
Thus, the expression equivalent to [tex]\(\frac{\log _2 128}{\log _2 16}\)[/tex] is [tex]\(\log_{16} 128\)[/tex].
Therefore, the correct choice is:
[tex]\[
\log_{16} 128
\][/tex]
One useful property is:
[tex]\[
\frac{\log_a b}{\log_a c} = \log_c b
\][/tex]
This tells us that when you divide two logarithms with the same base, you can rewrite it as a single logarithm with the denominator’s value as the new base and the numerator's value as the argument (or power that the base must be raised to).
Applying this property to our expression:
[tex]\[
\frac{\log_2 128}{\log_2 16} = \log_{16} 128
\][/tex]
Thus, the expression equivalent to [tex]\(\frac{\log _2 128}{\log _2 16}\)[/tex] is [tex]\(\log_{16} 128\)[/tex].
Therefore, the correct choice is:
[tex]\[
\log_{16} 128
\][/tex]
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