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Answer :
We start by comparing the atomic radii of the given elements. The approximate atomic radii (in picometers) are:
[tex]$$
\begin{aligned}
\text{Oxygen (O)} &\approx 66 \, \text{pm} \\
\text{Carbon (C)} &\approx 77 \, \text{pm} \\
\text{Tin (Sn)} &\approx 141 \, \text{pm} \\
\text{Strontium (Sr)} &\approx 215 \, \text{pm}
\end{aligned}
$$[/tex]
To arrange these elements from smallest to largest atomic radius, we start with the smallest value and work our way up:
1. Smallest radius: Oxygen ([tex]$66$[/tex] pm).
2. Next: Carbon ([tex]$77$[/tex] pm).
3. Then: Tin ([tex]$141$[/tex] pm).
4. Largest radius: Strontium ([tex]$215$[/tex] pm).
Hence, the order from smallest to largest is:
[tex]$$\text{O}, \text{C}, \text{Sn}, \text{Sr}.$$[/tex]
This corresponds to option B.
[tex]$$
\begin{aligned}
\text{Oxygen (O)} &\approx 66 \, \text{pm} \\
\text{Carbon (C)} &\approx 77 \, \text{pm} \\
\text{Tin (Sn)} &\approx 141 \, \text{pm} \\
\text{Strontium (Sr)} &\approx 215 \, \text{pm}
\end{aligned}
$$[/tex]
To arrange these elements from smallest to largest atomic radius, we start with the smallest value and work our way up:
1. Smallest radius: Oxygen ([tex]$66$[/tex] pm).
2. Next: Carbon ([tex]$77$[/tex] pm).
3. Then: Tin ([tex]$141$[/tex] pm).
4. Largest radius: Strontium ([tex]$215$[/tex] pm).
Hence, the order from smallest to largest is:
[tex]$$\text{O}, \text{C}, \text{Sn}, \text{Sr}.$$[/tex]
This corresponds to option B.
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