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The length of a violin string, \( l \), varies inversely as the frequency of its vibrations, \( f \). When the length increases, the frequency decreases, and when the length decreases, the frequency increases.

A violin string 18 inches long vibrates at a frequency of 350 cycles per second. Find the frequency of a 15-inch violin string. Explain how you solved it.

Answer :

Final answer:

The length of a violin string and its frequency of vibrations are inversely proportional. Using the formula for inverse variation, we can determine the frequency of a 15-inch violin string.


Explanation:

The relationship between the length of a violin string, l, and the frequency of its vibrations, f, is described as inversely proportional. This means that as the length increases, the frequency decreases, and vice versa.

To solve the problem, we can use the formula for inverse variation:

l1 * f1 = l2 * f2

Where l1 and f1 represent the initial values (length and frequency) and l2 and f2 represent the new values we want to find.

Using the given values, we have:

18 * 350 = 15 * f2

From this equation, we can solve for f2, which represents the frequency of a 15-inch violin string.

f2 = (18 * 350) / 15 = 420 cycles per second.


Learn more about Inverse variation here:

https://brainly.com/question/26149612


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