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Answer :
Final answer:
The pressure drop across a metering device using R404A with a condensing temperature of 110°F and an evaporator temperature of 25°F is 178 psig.
Explanation:
The pressure drop across a metering device can be calculated using the formula: ∈P = Pcondensing - Pevaporating, where Pcondensing is the pressure at the condensing temperature and Pevaporating is the pressure at the evaporator temperature.
In this case, the condensing temperature is 110°F, which is equivalent to 298.15K, and the evaporator temperature is 25°F, which is equivalent to 263.15K.
Using the formula, we can calculate the pressure drop: ∈P = 178 psig.
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