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Un jardín de forma triangular mide 150 cm en cada uno de sus lados. El dueño quiere cercarlo con 7 vueltas de alambre.

¿Cuántos centímetros de alambre se necesitan?

¿Cuánto dinero se necesita si cada centímetro de alambre cuesta 2 pesos?

Answer :

The total amount needed to purchase the required amount of wire to fence the triangular-shaped garden would be 6, 300 Pesos.

How to find the cost ?

Since all three sides of the garden are 150 cm each, you can simply multiply 150 cm by 3 to find the perimeter:

Perimeter = 3 * 150 cm

= 450 cm

Multiply the perimeter by 7 to account for the turns:

Total Length of Wire = 7 * Perimeter

= 7 * 450 cm

= 3, 150 cm

You need 3, 150 centimeters of wire to fence the garden.

If each centimeter of wire costs 2 pesos, you can find the total cost by multiplying the length of wire by the cost per centimeter:

Total Cost = Total Length of Wire * Cost per Centimeter

Total Cost = 3150 cm * 2 pesos/cm

= 6, 300 pesos

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