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A 7.5 kg cannonball leaves a cannon with a speed of 185 meters per second. Find the average net force applied to the ball if the cannon muzzle is 3.6 meters long.

Answer :

Answer:

F = 35651 [N]

Explanation:

To solve this problem we must use the following equation of kinematics

[tex]v_{f} ^{2} =v_{o} ^{2} +2*a*x[/tex]

where:

Vf = final velocity = 185 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

x = distance = 3.6 [m]

Now we can find the acceleration.

185² = 0 + 2*a*3.6

34225 = 7.2*a

a = 4753.47 [m/s²]

Now we must use Newton's second law which tells us that the total force on a body is equal to the product of mass by acceleration.

F = m*a

where:

m = mass = 7.5 [kg]

F = force [N] (units of Newtons)

F = 7.5*4753.47

F = 35651 [N]

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