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Answer :
Let's approach this problem step by step.
### Part (a): Finding the Domain
The chirp rate function given is:
[tex]\[ C = f(T) = 4T - 160 \][/tex]
To find the domain of [tex]\( f \)[/tex], we need to determine the range of temperatures [tex]\( T \)[/tex] for which this function is valid. The context of the model states that the highest recorded temperature at a weather station is [tex]\( 134^{\circ} F \)[/tex].
1. Let's first find the lower limit of [tex]\( T \)[/tex]. For the chirp rate [tex]\( C \)[/tex] to make sense, it must be non-negative because a negative chirp rate is not physically meaningful:
[tex]\[ 4T - 160 \geq 0 \][/tex]
Solving this inequality for [tex]\( T \)[/tex]:
[tex]\[ 4T \geq 160 \][/tex]
[tex]\[ T \geq 40 \][/tex]
2. The upper limit of [tex]\( T \)[/tex] is given as [tex]\( 134^{\circ} F \)[/tex].
Putting this information together, the domain of [tex]\( f \)[/tex] is:
[tex]\[ 40 \leq T \leq 134 \][/tex]
### Part (b): Finding the Range
Next, we need to find the range of [tex]\( f \)[/tex] on the domain we found. Specifically, we need to calculate the chirp rates at the minimum and maximum temperatures in this domain.
1. For the minimum temperature [tex]\( T = 40 \)[/tex]:
[tex]\[ C = 4(40) - 160 = 160 - 160 = 0 \][/tex]
2. For the maximum temperature [tex]\( T = 134 \)[/tex]:
[tex]\[ C = 4(134) - 160 = 536 - 160 = 376 \][/tex]
Thus, the range of [tex]\( f \)[/tex] is:
[tex]\[ 0 \leq C \leq 376 \][/tex]
### Summary
- Domain of [tex]\( f \)[/tex]:
[tex]\[ 40 \leq T \leq 134 \][/tex]
- Range of [tex]\( f \)[/tex]:
[tex]\[ 0 \leq C \leq 376 \][/tex]
So, your answers are:
(a) Domain of [tex]\( f \)[/tex] is [tex]\( 40 \leq T \leq 134 \)[/tex].
(b) Range of [tex]\( f \)[/tex] is [tex]\( 0 \leq C \leq 376 \)[/tex].
### Part (a): Finding the Domain
The chirp rate function given is:
[tex]\[ C = f(T) = 4T - 160 \][/tex]
To find the domain of [tex]\( f \)[/tex], we need to determine the range of temperatures [tex]\( T \)[/tex] for which this function is valid. The context of the model states that the highest recorded temperature at a weather station is [tex]\( 134^{\circ} F \)[/tex].
1. Let's first find the lower limit of [tex]\( T \)[/tex]. For the chirp rate [tex]\( C \)[/tex] to make sense, it must be non-negative because a negative chirp rate is not physically meaningful:
[tex]\[ 4T - 160 \geq 0 \][/tex]
Solving this inequality for [tex]\( T \)[/tex]:
[tex]\[ 4T \geq 160 \][/tex]
[tex]\[ T \geq 40 \][/tex]
2. The upper limit of [tex]\( T \)[/tex] is given as [tex]\( 134^{\circ} F \)[/tex].
Putting this information together, the domain of [tex]\( f \)[/tex] is:
[tex]\[ 40 \leq T \leq 134 \][/tex]
### Part (b): Finding the Range
Next, we need to find the range of [tex]\( f \)[/tex] on the domain we found. Specifically, we need to calculate the chirp rates at the minimum and maximum temperatures in this domain.
1. For the minimum temperature [tex]\( T = 40 \)[/tex]:
[tex]\[ C = 4(40) - 160 = 160 - 160 = 0 \][/tex]
2. For the maximum temperature [tex]\( T = 134 \)[/tex]:
[tex]\[ C = 4(134) - 160 = 536 - 160 = 376 \][/tex]
Thus, the range of [tex]\( f \)[/tex] is:
[tex]\[ 0 \leq C \leq 376 \][/tex]
### Summary
- Domain of [tex]\( f \)[/tex]:
[tex]\[ 40 \leq T \leq 134 \][/tex]
- Range of [tex]\( f \)[/tex]:
[tex]\[ 0 \leq C \leq 376 \][/tex]
So, your answers are:
(a) Domain of [tex]\( f \)[/tex] is [tex]\( 40 \leq T \leq 134 \)[/tex].
(b) Range of [tex]\( f \)[/tex] is [tex]\( 0 \leq C \leq 376 \)[/tex].
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