We appreciate your visit to A 2 kg mass hangs motionless from a partially stretched spring having a spring constant of 172 N m What is the magnitude of the. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The total force required to pull a 2kg mass down an additional 5cm against a spring with a spring constant of 172 N/m, while it's under the influence of gravity, is 28.2 N.
Explanation:
The question falls under the subject of physics, specifically dealing with Hooke's Law (F=kx) and gravitational force (F=mg). In the given question, a 2 kg mass hangs motionless from a spring, meaning that the force due to gravity is balanced by the force exerted by the spring.
The force from gravity, F, can be calculated with the formula F=mg. Thus, for a 2 kg mass and the acceleration due to gravity, g, equals 9.8 m/s², F equals 2 kg * 9.8 m/s² = 19.6 N. Next, we use Hooke's law to calculate the force required to stretch the spring an additional 5 cm (0.05m), which is F = kx = 172 N/m * 0.05 m = 8.6 N.
To find the total force required to pull down the mass we add the force of gravity and the force required by Hooke's law together. Therefore, the total force required to pull the mass down by an additional 5cm is 19.6 N + 8.6 N = 28.2 N.
Learn more about Hooke's Law and Gravitational Force here:
https://brainly.com/question/30379950
#SPJ11
Thanks for taking the time to read A 2 kg mass hangs motionless from a partially stretched spring having a spring constant of 172 N m What is the magnitude of the. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
The magnitude of the force required to pull the mass down by an additional 5 cm is 8.6 N.
To find the force required to stretch the spring by an additional 5 cm, we can use Hooke's Law, which states that the force exerted by a spring is proportional to the displacement from its equilibrium position and is given by the equation:
[tex]\[ F = k \cdot x \][/tex]
where ( F ) is the force exerted by the spring, ( k ) is the spring constant, and ( x ) is the displacement from the equilibrium position.
Given:
- The mass m = 2 kg (which is not directly relevant to the spring force calculation).
- The spring constant k = 172 N/m.
- The additional displacement x = 5 cm, which needs to be converted to meters for consistency in units: x = 0.05 m.
Now, we apply Hooke's Law to find the force:
[tex]\[ F = k \cdot x = 172 \text{ N/m} \cdot 0.05 \text{ m} \][/tex]
[tex]\[ F = 8.6 \text{ N} \][/tex]
Therefore, the magnitude of the force required to pull the mass down by an additional 5 cm is 8.6 N. Note that the mass of the object hanging from the spring does not affect the force required to stretch the spring by a given distance, as long as the spring is ideal and follows Hooke's Law. The mass would only affect the initial stretch of the spring from its unstretched length.
