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A toy store employee counted the number of toys in each bin in the sale section. The distribution of toys per bin is as follows:

6, 6, 6, 6, 18, 18, 18, 18, 18, 18, 18, 18, 18, 93, 93, 93, 93, 93, 93, 93.

Let \( X \) be the number of toys that a randomly chosen bin has. What is the expected value of \( X \)? Write your answer as a decimal.

Answer :

We get that the expected value is

[tex]E(X)=\frac{6\cdot4+18\cdot9+93\cdot7}{20}=41.85[/tex]

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