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Answer :
To solve the division of numbers in binary base (base 2), let's look at each part of the question step by step.
### Understanding the Problem
We need to perform divisions where numbers are given in binary. Let's go through the examples one by one:
#### Example (1): [tex]\( 112 \div 112 \)[/tex]
When writing numbers in binary, each digit represents a power of 2. However, it seems there might be a mistake in the digit '2' appearing in the sequence '112', as valid binary digits are only 0 and 1. So, let's interpret this assuming it's an error.
Let's translate '11' in binary:
- Binary "11": This is equivalent to [tex]\(1 \times 2^1 + 1 \times 2^0 = 2 + 1 = 3\)[/tex] in decimal.
Since both the dividend and divisor here are identical ('11' in binary), this division is:
[tex]\[ 3 \div 3 = 1 \][/tex]
So, the result of this operation is 1.
### Final Result
Based on the steps we took, even with the assumption that there might be a slight misunderstanding in binary notation, dividing identical numbers in any base results in 1. Therefore, the result for the division [tex]\( 112 \div 112 \)[/tex] is indeed 1.
### Understanding the Problem
We need to perform divisions where numbers are given in binary. Let's go through the examples one by one:
#### Example (1): [tex]\( 112 \div 112 \)[/tex]
When writing numbers in binary, each digit represents a power of 2. However, it seems there might be a mistake in the digit '2' appearing in the sequence '112', as valid binary digits are only 0 and 1. So, let's interpret this assuming it's an error.
Let's translate '11' in binary:
- Binary "11": This is equivalent to [tex]\(1 \times 2^1 + 1 \times 2^0 = 2 + 1 = 3\)[/tex] in decimal.
Since both the dividend and divisor here are identical ('11' in binary), this division is:
[tex]\[ 3 \div 3 = 1 \][/tex]
So, the result of this operation is 1.
### Final Result
Based on the steps we took, even with the assumption that there might be a slight misunderstanding in binary notation, dividing identical numbers in any base results in 1. Therefore, the result for the division [tex]\( 112 \div 112 \)[/tex] is indeed 1.
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