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Answer :
The period of the ball in simple harmonic motion is 0.634 s.
What is period?
Period can be defined as the time ( in seconds) taken for a body to complete one oscillation.
To calculate the period of the ball in SHM, we use the formula below.
Formula:
- T = 2π√(m/k)............... Equation 1
Where:
- T = Period of the ball
- m = mass of the ball
- k = spring constant
- π = pie
From the question,
Given:
- m = 2 kg
- k = 196 N/m
- π = 3.14
Substitute these values into equation 1
- T = 2(3.14)√(2/196)
- T = 6.28√(0.010204)
- T = 0.634 s
Hence, The period of the ball in simple harmonic motion is 0.634 s.
Learn more about period here: https://brainly.com/question/21924087
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Final answer:
The period of a ball attached to a vertical spring in simple harmonic motion can be calculated using the formula T = 2π√(m/k), where T is the period, m is the mass of the object, and k is the spring constant. Plugging in the values for mass and spring constant, the period is approximately 0.633 s.
Explanation:
The period of a simple harmonic motion (SHM) of an object attached to a vertical spring can be calculated using the formula:
T = 2π√(m/k)
where T is the period, m is the mass of the object, and k is the spring constant.
For the given problem, the mass of the ball is 2.0 kg and the spring constant is 196 N/m. Plugging these values into the formula:
T = 2π√(2.0/196) ≈ 0.633 s
Therefore, the period of the ball in SHM is approximately 0.633 s.
