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You've set a goal of having [tex]$\$10,000$[/tex] after 15 years. If you estimate that your investment account will have an average yearly factor of 1.09, which equation could be used to calculate how much you should invest today?

A. [tex]$y = 10000(0.09)^{15}$[/tex]

B. [tex]$y = 10000(1.09)^{15}$[/tex]

C. [tex]$10000 = x(0.09)^{15}$[/tex]

D. [tex]$10000 = x(1.09)^{15}$[/tex]

Answer :

To solve this problem, we need to determine which equation can help us calculate the amount of money to invest today so that it grows to [tex]$10,000 in 15 years, given an average yearly growth factor of 1.09.

1. Understand the problem:
- We want to have $[/tex]10,000 in the future (after 15 years).
- The annual growth factor of the investment is 1.09, meaning each year the investment grows by 9%.

2. We use the formula for compound interest, which is:
[tex]\[
\text{Future Value} = \text{Present Value} \times (\text{Growth Factor})^{\text{Years}}
\][/tex]
In this context:
- Future Value = $10,000
- Growth Factor = 1.09
- Years = 15
- Present Value = x (the amount we need to find)

3. Plug the known values into the compound interest formula:
[tex]\[
10000 = x \times (1.09)^{15}
\][/tex]

4. We need to solve for x, which represents the Present Value or the amount to invest today:
- Rearrange the equation to solve for x:
[tex]\[
x = \frac{10000}{(1.09)^{15}}
\][/tex]

5. Match this equation with the given options:
- The equation that matches our derived formula is:
[tex]\[
10000 = x(1.09)^{15}
\][/tex]
- This corresponds to option D.

Therefore, the correct equation to calculate the initial investment needed is option D: [tex]\(10000 = x(1.09)^{15}\)[/tex].

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