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Which line is perpendicular to a line that has a slope of [tex]-\frac{5}{6}[/tex]?

A. Line JK
B. Line LM
C. Line NO
D. Line PQ

Answer :

To determine which line is perpendicular to a line that has a slope of [tex]\(-\frac{5}{6}\)[/tex], we need to find the slope of the perpendicular line.

Here's how you can do it:

1. Understand Perpendicular Slopes: Two lines are perpendicular if the product of their slopes is [tex]\(-1\)[/tex]. This means if you have the slope of one line, the slope of the line perpendicular to it is the negative reciprocal.

2. Find the Negative Reciprocal: The given line has a slope of [tex]\(-\frac{5}{6}\)[/tex].
- The reciprocal of [tex]\(-\frac{5}{6}\)[/tex] is [tex]\(-\frac{6}{5}\)[/tex].
- Then, change the sign: the negative reciprocal is [tex]\(\frac{6}{5}\)[/tex].

3. Use the Negative Reciprocal to Identify the Perpendicular Line: We now know that the slope of the line perpendicular to the original line (with slope [tex]\(-\frac{5}{6}\)[/tex]) is [tex]\(\frac{6}{5}\)[/tex].

4. Check the Options: Without specific slopes provided for lines JK, LM, NO, and PQ, we identify the line whose slope is [tex]\(\frac{6}{5}\)[/tex]. In a typical question, it would involve checking each line's slope to find which one matches [tex]\(\frac{6}{5}\)[/tex].

In conclusion, the line that has a slope of [tex]\(\frac{6}{5}\)[/tex] is the one perpendicular to the given line with slope [tex]\(-\frac{5}{6}\)[/tex].

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