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Answer :
Explanation:
According to the given situation, angle made by the reflected ray with the ground is as follows.
[tex]\theta = tan^{-1} (\frac{37.9}{21.7})[/tex]
= [tex]60.2^{o}[/tex]
Therefore, according to the geometry of the figure.
[tex]\theta_{r} = 90^{o} - 60.2^{o}[/tex]
= [tex]29.8^{o}[/tex]
Since, the angle of incidence is equal to the angle of reflection.
So, [tex]\theta_{i} = \theta_{r}[/tex]
= [tex]29.8^{o}[/tex]
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