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The population, [tex]p[/tex], of a town after [tex]t[/tex] years is represented using the equation [tex]p=10000(1.04)^{-t}[/tex]. Which of the following is an equivalent expression?

A. [tex]p=10000\left(\frac{1}{25}\right)^t[/tex]

B. [tex]p=10000\left(\frac{25}{26}\right)^t[/tex]

C. [tex]p=10000\left(\frac{26}{25}\right)^t[/tex]

D. [tex]p=10000\left(\frac{25}{1}\right)^t[/tex]

Answer :

Sure! Let's find the equivalent expression step-by-step.

The original equation given for the population, [tex]\( p \)[/tex], is:

[tex]\[ p = 10000(1.04)^{-t} \][/tex]

The problem is asking us to find an equivalent expression. We need to rewrite [tex]\( (1.04)^{-t} \)[/tex] in a different form.

### Steps to Solve:

1. Understanding Negative Exponents:
The expression [tex]\( (1.04)^{-t} \)[/tex] can be rewritten because a negative exponent means taking the reciprocal. Therefore:

[tex]\[ (1.04)^{-t} = \left(\frac{1}{1.04}\right)^{t} \][/tex]

2. Convert 1.04 to a Fraction:
The decimal 1.04 can be written as a fraction:

[tex]\[ 1.04 = \frac{26}{25} \][/tex]

3. Finding the Reciprocal of the Fraction:
Now we find the reciprocal of [tex]\( \frac{26}{25} \)[/tex]:

[tex]\[ \frac{1}{1.04} = \frac{1}{\frac{26}{25}} = \frac{25}{26} \][/tex]

4. Substitute Back into the Expression:
Replace [tex]\( \left(\frac{1}{1.04}\right)^{t} \)[/tex] with [tex]\( \left(\frac{25}{26}\right)^{t} \)[/tex]:

[tex]\[ p = 10000\left(\frac{25}{26}\right)^{t} \][/tex]

### Conclusion:

The equivalent expression to [tex]\( p = 10000(1.04)^{-t} \)[/tex] is:

[tex]\[ p = 10000\left(\frac{25}{26}\right)^{t} \][/tex]

So, the correct option is:

[tex]\( p = 10000\left(\frac{25}{26}\right)^t \)[/tex]

This matches the second option in the list provided.

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