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A dose of 40 mEq KCl has been added to 1 L of normal saline. What drip rate would provide a patient with 1 mEq KCl per hour?

Answer :

Given, a dose of 40 m eq k cl has been added to 1 L of normal saline. We need to determine the drip rate that would provide a patient with 1 m eq K Cl/h. Drip rate = ((Volume × Flow rate × Drip factor)/Time in minutes)Calculation of drip rate

1. Convert 1 L to mL .Volume = 1 L × 1000 mL/L = 1000 mL2. Use the formula to calculate drip rate:((1000 × flow rate × 15)/60) = 1 m eq/h × 40(1000 × flow rate × 15) = 60 × 40flow rate = (60 × 40)/(1000 × 15)flow rate = 0.16 mL/ min Therefore, the drip rate that would provide a patient with 1 m eq K Cl/h is 0.16 mL/min.

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