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Suppose the scores of seven members of a women's golf team are [tex]$68, 62, 60, 64, 70, 66, 72$[/tex]. Find the mean, median, and midrange.

a. Mean [tex]$= 64$[/tex], median [tex]$= 64$[/tex], midrange [tex]$= 64$[/tex]

b. Mean [tex]$= 65$[/tex], median [tex]$= 64$[/tex], midrange [tex]$= 66$[/tex]

c. Mean [tex]$= 66$[/tex], median [tex]$= 77$[/tex], midrange [tex]$= 65$[/tex]

d. Mean [tex]$= 66$[/tex], median [tex]$= 66$[/tex], midrange [tex]$= 66$[/tex]

Please select the best answer from the choices provided:

A

B

C

D

Answer :

Sure! Let's find the mean, median, and midrange of the scores from the women's golf team, which are 68, 62, 60, 64, 70, 66, and 72.

1. Mean:
The mean is the average of the numbers. To find it, add all the scores together and then divide by the number of scores.
[tex]\[
\text{Mean} = \frac{68 + 62 + 60 + 64 + 70 + 66 + 72}{7} = \frac{522}{7} = 66
\][/tex]

2. Median:
The median is the middle number in a sorted, ascending list of numbers. To find it, first arrange the scores in order:
[tex]\[
60, 62, 64, 66, 68, 70, 72
\][/tex]
Since there are 7 scores, the median is the fourth number in this ordered list, which is 66.

3. Midrange:
The midrange is the average of the smallest and largest numbers in the list.
[tex]\[
\text{Midrange} = \frac{\text{Smallest} \, + \, \text{Largest}}{2} = \frac{60 + 72}{2} = \frac{132}{2} = 66
\][/tex]

From these calculations, the mean is 66, the median is 66, and the midrange is 66. Therefore, the correct answer is:

d. Mean = 66, median = 66, midrange = 66

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