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Answer :
The percent of the heights of the class which has an average height of 68 inches and a standard deviation of 2 inches that will exceed 72 inches is 2.28%.
How the percentage is computed:
We can use the normal distribution calculator to compute the percentage of the heights that will exceed 72 inches, using the following parameters and the z-score, as follows:
The average height of the class = 68 inches
Standard deviation = 2 inches
Sample mean = 72 inches
z score (standard measure) = (x - mean) / standard deviation
z = (72 - 68) / 2
z = 2
The probability that z is greater than 2, using the normal distribution calculator, gives us an area of 0.0228.
Thus, the percent of the heights that will exceed 72 inches is 2.28%.
Learn more about normal distribution at https://brainly.com/question/4079902.
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