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Answer :
The IQ below which a child would be eligible to apply for the education assistance program is 71.
To find the IQ below which a child would be eligible to apply for the education assistance program, we need to find the value of X such that it corresponds to the bottom 5% of the normal distribution of IQ scores.
Given data:
Mean (μ) = 96
Standard Deviation (σ) = 15
Use the standard normal distribution (Z-score) formula to find the value of X:
Z = (X - μ) / σ
In this case, we want to find the Z-score that corresponds to the 5th percentile, which is -1.645 according to the standard normal distribution table.
Now we can solve for X:
-1.645 = (X - 96) / 15
Solving for X:
X - 96 = -1.645 × 15
X - 96 = -24.675
Add 96 on both sides:
X = 96 - 24.675
X = 71.325
Hence, the IQ below which a child would be eligible to apply for the education assistance program is approximately 71.
To learn more on Statistics click:
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