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Practice proving that a quadrilateral is a parallelogram.

In quadrilateral [tex]WXYZ[/tex], if [tex]WC = 2x + 5[/tex] and [tex]CY = 3x + 2[/tex], what must [tex]x[/tex] equal for quadrilateral [tex]WXYZ[/tex] to be a parallelogram?

[tex]x = \square[/tex]

Answer :

To prove that a quadrilateral is a parallelogram, one of the ways is to show that opposite sides are equal.

In this problem, you're given expressions for two sides of quadrilateral [tex]\(WXYZ\)[/tex]:
- [tex]\( WC = 2x + 5 \)[/tex]
- [tex]\( CY = 3x + 2 \)[/tex]

For [tex]\(WXYZ\)[/tex] to be a parallelogram, the opposite sides must be equal, so we set these two expressions equal to each other:

[tex]\[ 2x + 5 = 3x + 2 \][/tex]

Now, let's solve the equation for [tex]\(x\)[/tex]:

1. Subtract [tex]\(2x\)[/tex] from both sides to get:
[tex]\[ 5 = x + 2 \][/tex]

2. Subtract 2 from both sides to isolate [tex]\(x\)[/tex]:
[tex]\[ 5 - 2 = x \][/tex]

3. Simplify the left side to find:
[tex]\[ 3 = x \][/tex]

Therefore, for the quadrilateral [tex]\(WXYZ\)[/tex] to be a parallelogram, [tex]\(x\)[/tex] must equal 3.

Thanks for taking the time to read Practice proving that a quadrilateral is a parallelogram In quadrilateral tex WXYZ tex if tex WC 2x 5 tex and tex CY 3x 2 tex. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

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