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Answer :
The car's acceleration while braking was approximately -0.0644 m/h². This was determined using the kinematic equation v² = u² + 2as and solving for acceleration.
The distance traveled was converted to meters to apply the formula correctly. To find the acceleration of the car, we can use the kinematic equation:
v² = u² + 2as
where:
- v is the final velocity (0 m/h, as the car stops)
- u is the initial velocity (50.0 m/h)
- a is the acceleration
- s is the distance (19.4 km; converted to meters: 19,400 m)
Rearranging the equation to solve for acceleration, a:
a = (v² - u²) / (2s)
Substituting in the values:
a = (0² - (50.0)²) / (2 × 19,400)
a = -2500 / 38,800
a ≈ -0.0644 m/h²
This means the car's acceleration while braking was approximately -0.0644 m/h².
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