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An 14 kg block is pulled by a string up a 30° incline by a force of 112 N. Given that [tex]\mu = 0.15[/tex], find the acceleration of the block.

(Note: Ensure calculations are performed using degrees.)

Answer :

The acceleration of the block is 7.8 m/s².

What do you mean by acceleration?

The rate at which an object's velocity with respect to time changes is referred to as acceleration. It is a vector quantity to accelerate (in that they have magnitude and direction).

To find the acceleration of the block, we can use the equation:

force = mass X acceleration + friction

Rearranging the equation, we can find the acceleration:

acceleration = (force - friction) / mass

The force of friction can be found using the equation:

friction = friction coefficient X normal force

The normal force is equal to the weight of the object, which can be found using the equation:

weight = mass X gravity

So, friction = friction coefficient X mass X gravity

We know that gravity is 9.8 m/s²

friction = .15 * 14 kg * 9.8 m/s²

Now we can substitute this value for friction and the known values for force and mass into the first equation and solve for acceleration:

acceleration = (112 N - 1.47 N) / 14 kg

acceleration = 7.8 m/s²

So, the acceleration of the block is 7.8 m/s².

To know more about acceleration, visit:

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