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Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that of the offspring will be heterozygous.
```
| | W | w |
|---|----|----|
| w | Ww | ww |
| w | Ww | ww |
```

2. If the heterozygous, [tex]Ww[/tex], is crossed with a homozygous dominant, [tex]WW[/tex], then the probability of having a homozygous recessive offspring is
```
| | W | w |
|---|----|----|
| W | WW | Ww |
| W | WW | Ww |
```

Answer :

Sure, let's break down the given genetic crosses in detail to understand the probabilities of the offspring having certain genotypes.

### First Scenario:
A heterozygous male (genotype Ww) is mated with a homozygous recessive female (genotype ww).

Here is the Punnett square for this cross:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]

From the Punnett square:
- There are 2 outcomes of Ww.
- There are 2 outcomes of ww.

Therefore, out of 4 possible outcomes:
- The probability of having a heterozygous (Ww) offspring is 2 out of 4, which simplifies to 50%.

### Second Scenario:
A heterozygous (Ww) individual is crossed with a homozygous dominant (WW) individual.

Here is the Punnett square for this cross:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\][/tex]

From the Punnett square:
- There are 2 outcomes of WW.
- There are 2 outcomes of Ww.
- There are 0 outcomes of ww.

Hence, the probability of having a homozygous recessive (ww) offspring is 0%.

### Correct Answers to the Drop-Down Menus:
1. If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 50% chance that the offspring will be heterozygous.
2. If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0%.

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