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Answer :
To solve [tex]\( 163 \div 4 \)[/tex] with a detailed, step-by-step approach, let's break it down:
1. Set up the Division:
We need to divide 163 by 4.
2. Divide the First Digit(s):
- 4 goes into 16 a total of 4 times (since [tex]\( 4 \times 4 = 16 \)[/tex]).
- Write 4 above the 6 in 163.
3. Subtract and Bring Down the Next Digit:
- Subtract [tex]\( 16 \)[/tex] from [tex]\( 16 \)[/tex] (which is the number we've used so far): [tex]\( 16 - 16 = 0 \)[/tex].
- Bring down the next digit, which is 3, making the number now [tex]\(\ 03 \)[/tex].
4. Divide Again:
- 4 goes into 3 a total of 0 times (since [tex]\( 4 \times 0 = 0 \)[/tex]).
- Write 0 above the 3 next to the 4.
5. Subtract Again:
- Subtract [tex]\( 0 \)[/tex] from [tex]\( 3 \)[/tex]: [tex]\( 3 - 0 = 3 \)[/tex].
The quotient when 163 is divided by 4 is 40, and the remainder is 3.
Thus, the division problem [tex]\(163 \div 4\)[/tex] results in a quotient of 40 with a remainder of 3. So, we can write it as:
[tex]\[ \frac{163}{4} = 40 \text{ R } 3 \][/tex]
Or in fractional form:
[tex]\[ 163 \div 4 = 40 \text{ remainder } 3\][/tex]
1. Set up the Division:
We need to divide 163 by 4.
2. Divide the First Digit(s):
- 4 goes into 16 a total of 4 times (since [tex]\( 4 \times 4 = 16 \)[/tex]).
- Write 4 above the 6 in 163.
3. Subtract and Bring Down the Next Digit:
- Subtract [tex]\( 16 \)[/tex] from [tex]\( 16 \)[/tex] (which is the number we've used so far): [tex]\( 16 - 16 = 0 \)[/tex].
- Bring down the next digit, which is 3, making the number now [tex]\(\ 03 \)[/tex].
4. Divide Again:
- 4 goes into 3 a total of 0 times (since [tex]\( 4 \times 0 = 0 \)[/tex]).
- Write 0 above the 3 next to the 4.
5. Subtract Again:
- Subtract [tex]\( 0 \)[/tex] from [tex]\( 3 \)[/tex]: [tex]\( 3 - 0 = 3 \)[/tex].
The quotient when 163 is divided by 4 is 40, and the remainder is 3.
Thus, the division problem [tex]\(163 \div 4\)[/tex] results in a quotient of 40 with a remainder of 3. So, we can write it as:
[tex]\[ \frac{163}{4} = 40 \text{ R } 3 \][/tex]
Or in fractional form:
[tex]\[ 163 \div 4 = 40 \text{ remainder } 3\][/tex]
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