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The atomic mass of potassium is 39.1. What is the mass of [tex]6.02 \times 10^{23}[/tex] atoms of potassium?

A. [tex]39.1 \, \text{mg}[/tex]
B. [tex]39.1 \, \text{g}[/tex]
C. [tex]39.1 \, \text{kg}[/tex]
D. [tex]6.02 \times 39.1 \, \text{mg}[/tex]
E. [tex]6.02 \times 39.1 \, \text{g}[/tex]

Answer :

To solve the problem, follow these steps:

1. The atomic mass of potassium is given as [tex]$39.1$[/tex]. This means that one mole of potassium, which is defined as [tex]$6.02 \times 10^{23}$[/tex] atoms, has a mass of [tex]$39.1$[/tex] grams.

2. Since the number of atoms provided is exactly [tex]$6.02 \times 10^{23}$[/tex], this corresponds directly to one mole of potassium.

3. Therefore, the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium is [tex]$39.1$[/tex] grams.

Thus, the correct answer is:

[tex]$$\textbf{B. } 39.1\, \text{g}$$[/tex]

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