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When the same voltage is applied to a 25-W and a 40-W lightbulb, the 40-W lightbulb burns brighter as your intuition may suggest. Which lightbulb has the higher resistance?

Answer :

Final answer:

Given the same voltage, the 40-W lightbulb has lower resistance compared to the 25-W lightbulb, hence it burns brighter. This is a principle of the formula P = V²/R, where power is inversely proportional to resistance for a fixed voltage.

Explanation:

The power consumed by a device (in this case, a lightbulb) is given by the formula P = V²/R, where P is the power, V the voltage, and R the resistance. In this scenario, if the voltage

is the same for both the bulbs, the bulb with a higher wattage (40-W), according to the formula, would have a lower resistance compared to the 25-W bulb. This is because power is directly proportional to resistance in the equation. Therefore, the

25-W bulb has higher resistance

than the 40-W bulb when the same voltage is applied to both.

Learn more about Electrical Resistance here:

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