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Answer :
Given data:
The first coordinate is J(9,-3).
The second coordinate is K(-1,5).
The slope of the line passing through the given points is,
[tex]\begin{gathered} m=\frac{5-(-3)}{-1-9} \\ =\frac{8}{-10} \\ =-0.8 \end{gathered}[/tex]The slope of the line LM perpendicular to it is,
[tex]\begin{gathered} m^{\prime}\times m=-1 \\ m^{\prime}\times(-0.8)=-1 \\ m=\frac{1}{0.8} \\ =\frac{5}{4} \end{gathered}[/tex]Thus, the slope of the LM line is 5/4.
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