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Answer :
a) Natural Unit Weight of Soil (γn): 1.84 g/cm³
b) Natural Water Content of Soil (wn): 9.89%
c) Dry Unit Weight of Soil Sample (γd): 1.67 g/cm³
d) Void Ratio (e): 0.67
e) Porosity (n): 0.40
f) Volume of Air (Va): 1.978 cm³
g) Final Water Content (wf): 9.89% and Final Unit Weight of Saturated Soil (γn final = γsat): 1.85 g/cm³
How did we get these values?
To solve this problem, we'll need to apply various soil mechanics principles and equations. Let's start with each question:
a) Natural Unit Weight of Soil (γn):
The natural unit weight of soil is calculated using the formula:
γn = (Weight of soil in the ring + Weight of the ring) / Volume of the ring
γn = (97.8g - 61g) / 20cm³
γn = 36.8g / 20cm³
γn = 1.84 g/cm³
b) Natural Water Content of Soil (wn):
The natural water content of the soil can be calculated using the formula:
wn = [(Weight of soil in the ring - Weight of dry soil) / Weight of dry soil] × 100%
wn = [(97.8g - 89g) / 89g] × 100%
wn = (8.8g / 89g) × 100%
wn ≈ 9.89%
c) Dry Unit Weight of Soil Sample (γd):
The dry unit weight of the soil sample can be calculated using the formula:
γd = γn / (1 + wn)
γd = 1.84 g/cm³ / (1 + 0.0989)
γd ≈ 1.67 g/cm³
d) Void Ratio (e):
The void ratio (e) can be calculated using the formula:
e = (γd / γw) - 1
Where γw is the unit weight of water, which is approximately 1 g/cm³.
e = (1.67 g/cm³ / 1 g/cm³) - 1
e ≈ 0.67
e) Porosity (n):
The porosity (n) is related to the void ratio (e) as follows:
n = e / (1 + e)
n = 0.67 / (1 + 0.67)
n ≈ 0.40
f) Volume of Air (Va):
Va can be calculated using the formula:
Va = wn × Volume of soil in the ring
Va = 0.0989 × 20cm³
Va ≈ 1.978cm³
g) Final Water Content (wf) and Final Unit Weight (γn final = γsat):
When the soil is fully saturated while keeping the total volume constant, the final water content (wf) can be calculated using the formula:
wf = Va / (Volume of soil in the ring)
wf = 1.978cm³ / 20cm³
wf ≈ 0.0989 or 9.89%
The final unit weight (γn final = γsat) when fully saturated can be calculated as:
γn final = γd / (1 - wf)
γn final ≈ 1.67 g/cm³ / (1 - 0.0989)
γn final ≈ 1.85 g/cm³
So, the final unit weight of the saturated soil sample is approximately 1.85 g/cm³.
learn more about Porosity: https://brainly.com/question/13866233
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