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The mass of a single tungsten atom is [tex]3.05 \times 10^{-22}[/tex] grams. How many tungsten atoms would there be in 37.9 milligrams of tungsten?

Answer :

To find the number of tungsten atoms in 37.9 milligrams of tungsten, we first need to convert the mass from milligrams to grams. 1 milligram is equal to 10^-3 grams.

37.9 milligrams = 37.9 x 10^-3 grams = 0.03709 grams

Now we have the mass of tungsten in grams. Next, we need to find the number of atoms by dividing the mass of tungsten by the mass of a single tungsten atom.

0.03709 grams / (3.05 x 10^-22 grams/atom) = 12.16 x 10^21 atoms

Therefore, there would be 12.16 x 10^21 atoms of tungsten in 37.9 milligrams of tungsten.

Note: This is a very large number, it is more commonly expressed in scientific notation.

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Rewritten by : Barada

Answer:

N = M / mW = 4850 / (3.05 * 10-22) = 1.59 * 1025 atoms of tungsten.