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Answer :
The normal force acting on the mass can be given as,
[tex]N=mg[/tex]The frictional force acting on the box is,
[tex]f=\mu_kN[/tex]Substitute the known expression,
[tex]f=\mu_kmg[/tex]The work done by frictional force can be given as,
[tex]W=fd[/tex]Substitute the known expression,
[tex]W=\mu_kmgd[/tex]Substitute the known values in the equation,
[tex]\begin{gathered} W=(0.324)(16.6kg)(9.8m/s^2)(11.4\text{ m)(}\frac{1\text{ J}}{1kgm^2s^{-2}}) \\ \approx601\text{ J} \end{gathered}[/tex]Thus, the work done by the frictional force is 601 J.
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