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Answer :
Final answer:
To calculate the runner's straight-line distance back to her starting point, use the Pythagorean theorem. The runner is approximately 6.71 miles away from her starting point.
Explanation:
The problem given is a classic example of a two-dimensional vector displacement problem, where the jogger's movements are equivalent to vector additions. In this scenario, we can treat the jogger's movements as a right-angled triangle, with one leg representing the 6-mile journey west, and the other leg representing the 3-mile journey north.
Using the Pythagorean theorem, we can calculate the straight-line distance (hypotenuse) from her end-point back to the starting point by squaring the lengths of the two legs of the triangle, adding them together, and taking the square root of the sum:
Distance from starting point (d) = √((6 miles)² + (3 miles)²)
= √(36 + 9)
= √45
≈ 6.71 miles
The runner is approximately 6.71 miles away from her starting point if she plans to run straight back.
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6.71 miles is the distance runner has to jogfrom her starting point if she plans to run straight back
What is Trigonometry?
Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.
Given,
If a runner jogs 6 miles west
Let the path will be AB =6miles
Then jogs 3 miles north,
BC=3 miles
We need to find how far is the runner from her starting point if she plans to run straight back
Which means we need to find AC
Pythagoras' theorem is a fundamental relation in Euclidean geometry between the three sides of a right triangle.
AC²=AB²+BC²
AC²=6²+3²
AC²=36+9
AC²=45
Take square root on both sides
AC=√45
AC=6.71
Hence, 6.71 miles is the distance runner has to run from her starting point if she plans to run straight back
To learn more on trigonometry click:
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