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Answer :
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669 J
Right option is D.
Step by Step Explanation:
[tex] \sf Mass \: of \: water(m) = 16g \\ \\ \sf Specific \: heat \: of water(C) = 4.18J/g \\ \\ \sf Change \: in \: temperature ( \triangle T) = 100 - 90 = 10{ \degree}C[/tex]
- [tex] \sf \large \red{ Heat = mC\triangle T}[/tex]
Now substituting the required values.
[tex] \sf \hookrightarrow Heat = 16 \times 4.18 \times 10 \\ \\ \sf \hookrightarrow Heat = 668.8(approx) \\ \\ \blue {\boxed { \hookrightarrow{Heat = 669J }}}[/tex]
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