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Answer :
Final answer:
The unit cell edge length for a potassium atom in a body-centered cubic lattice is 524 pm. This is calculated using the formula a = 4r/sqrt(3), substituting the given radius of 227 pm. Therefore, the correct option is A
Explanation:
In body-centered cubic (bcc) lattice structures, the unit cell edge length 'a' is related to the radius 'r' of the atom by the equation a = 4r/sqrt(3). Given that the radius of potassium is 227 pm, you can substitute this value into the equation to find the edge length.
By mathematically solving, a = 4 x 227 pm / sqrt(3) = 524 pm.
You can confirm this is correct by noting that the option 'a. 524 pm' is available in the choices provided. So, the unit cell edge length for a potassium atom in a body-centered cubic lattice is 524 pm.
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