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Answer :
To write the polynomial in descending order, we need to arrange the terms starting with the highest power of [tex]\(x\)[/tex] and going to the lowest power. The given polynomial is:
[tex]\[ 3x^3 + 9x^7 - x + 4x^{12} \][/tex]
Here are the steps to rewrite it in descending order:
1. Identify the powers of [tex]\(x\)[/tex] in each term:
- The first term, [tex]\(4x^{12}\)[/tex], has an exponent of 12.
- The second term, [tex]\(9x^7\)[/tex], has an exponent of 7.
- The third term, [tex]\(3x^3\)[/tex], has an exponent of 3.
- The fourth term, [tex]\(-x\)[/tex], has an exponent of 1 (since [tex]\(-x\)[/tex] is the same as [tex]\(-x^1\)[/tex]).
2. Arrange the terms by descending exponents:
- Start with the highest power: [tex]\(x^{12}\)[/tex].
- Follow with the next highest: [tex]\(x^7\)[/tex].
- Then, [tex]\(x^3\)[/tex].
- Finally, [tex]\(x^1\)[/tex].
3. Write the polynomial in the new order:
[tex]\[ 4x^{12} + 9x^7 + 3x^3 - x \][/tex]
So, the polynomial written in descending order is:
[tex]\[ 4x^{12} + 9x^7 + 3x^3 - x \][/tex]
This corresponds to option C.
[tex]\[ 3x^3 + 9x^7 - x + 4x^{12} \][/tex]
Here are the steps to rewrite it in descending order:
1. Identify the powers of [tex]\(x\)[/tex] in each term:
- The first term, [tex]\(4x^{12}\)[/tex], has an exponent of 12.
- The second term, [tex]\(9x^7\)[/tex], has an exponent of 7.
- The third term, [tex]\(3x^3\)[/tex], has an exponent of 3.
- The fourth term, [tex]\(-x\)[/tex], has an exponent of 1 (since [tex]\(-x\)[/tex] is the same as [tex]\(-x^1\)[/tex]).
2. Arrange the terms by descending exponents:
- Start with the highest power: [tex]\(x^{12}\)[/tex].
- Follow with the next highest: [tex]\(x^7\)[/tex].
- Then, [tex]\(x^3\)[/tex].
- Finally, [tex]\(x^1\)[/tex].
3. Write the polynomial in the new order:
[tex]\[ 4x^{12} + 9x^7 + 3x^3 - x \][/tex]
So, the polynomial written in descending order is:
[tex]\[ 4x^{12} + 9x^7 + 3x^3 - x \][/tex]
This corresponds to option C.
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